*solved*

OK, so I what I want to do is create a 1-dimensional array that prints integers but only if the integer is not repeated. The problem is that I do not know how to check for integers that are duplicates. Here is the code I have for it so far:

The integer value "100" is repeated in this case. Anybody know what I should do?

This post has been edited by BurninLeo on Oct 27 2009, 04:15 PM

This might not even work, but it might! All this should do is take an integer array and take out all the repeated numbers... maybe D: I haven't used vb.NET in ages!

Not familiar with Visual Basic

but assuming it's like any other language, what I would do is something like this (except with correct syntax)

Basically puts another FOR loop inside your FOR loop, checking each number up to the current one to see if it's equal to the current one, and if it is, turns on a boolean.

This post has been edited by ChaosEmerl on Oct 27 2009, 02:03 PM

i want to try something that's less than O(n²)!!!

anyway so you don't want to print out any number that is duplicated (so in this case it won't print any 100s at all)? or just one instance of each set of duplicates?

numbers = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 15, 25, 35, 45, 55, 65, 75, 85, 95, 100} table.sort(numbers) dupes = { } for index = 1, #numbers do local current, next = numbers[index], numbers[index + 1] if not (current == next) and not dupes[current] then print(current) else dupes[current] = true end end

for example that won't print out any 100s

obviously not vb and yeah

EDIT: however this way only works reliably when you use it on a pre-sorted list which is what is being done in your example so

This post has been edited by Xgoff on Oct 27 2009, 02:36 PM

Yeah that's what I need right thur but the whole "next, current, previous" concepts aren't exactly present in VB

what I could do I suppose is check the sum of every index value to see whether or not it equals twice the number of the index value, and if it is, don't write it. But that seems rather tedious.

So this piece of code works, but the console window crashes cause I go out of the array range....um....how do I fix that...

This post has been edited by Lightning on Oct 27 2009, 03:29 PM

well they're just variables storing references to a[x] and a[x+1] so they aren't anything special

sdhfghsgdhfs I missed the part where you said you wanted to print it out, mine was way more than it needed to be ;_;

change my example to this and it should do what you want. Now it checks everything before i for duplicates, assuming i isn't 0, because then you'd go out of the array's range. Then it checks everything after i, assuming i isn't the maximum, because then it would also go out of range.